Open(String,LlDomFileMode,LlDomAccessMode) Method

In This Topic

The Open method opens the project file in parameter projectFile. If you want to open an existing project file you have to obey that the project type (list, label or card) matches the class.

Syntax

Visual Basic
C#
C++/CLI

'Declaration
 
Public Overloads Sub Open( _
   ByVal projectFile As String, _
   ByVal fileMode As LlDomFileMode, _
   ByVal accessMode As LlDomAccessMode _
)

public void Open( 
   string projectFile,
   LlDomFileMode fileMode,
   LlDomAccessMode accessMode
)

public:
void Open( 
   String^ projectFile,
   LlDomFileMode fileMode,
   LlDomAccessMode accessMode
)

Parameters

projectFile: File to open.
fileMode: Gets or sets if the file is to be read or created.
accessMode: Gets or sets the access mode for the file.

Requirements

Platforms: Windows 10 (Version 21H2 - 23H2), Windows 11 (21H2 - 22H2), Windows Server 2016 - 2022
.NET: .NET Framework 4.8, .NET 6, .NET 7, .NET 8

Reference

ProjectBase Class
ProjectBase Members
Overload List

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